Structural combinations from 4 IVM (fcc) to   Bcc lattices

Last update 2-24-2003

from A, B, C, D   to   A+B+C+D

 

(This is a Chart of the pattern of patterns)

 

 

I.     Combinations of 4 IVMs (A, B, C, D)

 

               [Combinations of 2, tetrahedral edges]

    1a.     2 Cubic nets

 

    A+B

        AB+CD   2 interpenetrating cubic nets (bcc)

    C+D

 

 

   1b.     4 Diamond nets

 

     A+C = AC

     B+C = BC

     A+D = AD

     B+D = BD

 

     [Combinations of 3, tetrahedral faces]

   2.      4 Rhombic Dodecahedral nets ABC, ABD, ACD, BCD ivm (see II-1b below)

 

    A+B+C = ABC

    A+B+D = ABD

    A+C+D = ACD

    B+C+D = BCD

 

 

3.             Combination of (I-1a), 2 cubic nets

 

AB+CD = 2 interpenetrating cubic nets = bcc lattice

 

 

II.    Combinations of 4 Diamond nets (AC, BC, AD, BD)  [I-1b]

 

      [Combinations of 2]

   1a.     Two Interpenetrating Diamond nets

 

AC+BD

          ACBD+BCAD    4 interpenetrating diamond nets (bcc)

BC+AD                                

 

 

   1b.     4 Rhombic Dodecahedral nets (RD nets), (see I-2)

 

AC+BC = D’ RD net = ABC ivm

AD+BD = C’ RD net = ABD ivm

AC+AD = B’ RD net = ACD ivm

BC+BD = A’ RD net = BCD ivm

 

 

     [Combinations of 3]

    2.     4 Half-filled RD nets   (of 3 diamond combinations)

 

AC+BC+BD = D’ RD net ½ filled by BD

AD+BD+AC = C’ RD net ½ filled by AC

AC+AD+BC = B’ RD net ½ filled by BC

BC+BD+AD = A’ RD net ½ filled by AD

 

3.             Combination of (II-1a), 2 interpenetrating diamond nets

 

ACBD+BCAD = 4 interpenetrating diamond nets = bcc

 

 

III.   Combinations of 4 RD nets (ACBC, ADBD, ACAD, BCBD)  [II-1b]

                                  

 

              [Combinations of 2]

   1a.    2 Coupler nets

           

            ACBC+ADBD = D’+C’= odd coupler

                                                       ACBC,ADBD+ACAD,BCBD =“Siamese Couplers”

                                                       =2 interpenetrating coupler nets = RITE net = (bcc)

ACAD+BCBD = B’+A’= even coupler

 

 

   1b.    4 Half-filled RD nets    (of 2 RD combinations), note the filling difference between III-1b and II-2

 

D’+B’ = ACBC+ACAD  = D’ RD net ½ filled by AD

C’+A’ = ADBD+BCBD  = C’ RD net ½ filled by BC

C’+B’ = ADBD+ACAD  = B’ RD net ½ filled by BD

     D’+A’ = ACBC+BCBD  = A’ RD net ½ filled by AC

 

     [Combinations of 3]

   2.      4 Three RD nets (degenerated? into pairs of odd and even coupler nets)

 

A’B’C’ = BCBD+ACAD+ADBD = 2 interpenetrating RD, B’+A’= even coupler net (ADBD is redundant)

A’B’D’ = BCBD+ACAD+ACBC = 2 interpenetrating RD, B’+A’= even coupler net               

A’C’D’ = BCBD+ADBD+ACBC = 2 interpenetrating RD, D’+C’= odd coupler net

B’C’D’ = ACAD+ADBD+ACBC = 2 interpenetrating RD, D’+C’= odd coupler net

 

 

3.                Combination of (III-1a), 2 coupler nets

 

ACBC,ADBD+ACAD,BCBD = 2 interpenetrating coupler nets = RITE net = bcc

 

 

IV.   Combinations of 4 Half Filled RD nets  [III-1b]

 

   1a.

 

   1b.

 

   2.

 

    3.

 

 

I.      Combinations of 4 IVMs (A, B, C, D)

 

[Combinations of 4]

   3.      Combination of all 4 IVMs

 

A+B+C+D = 4 IVM = bcc, including all the above pattern combinations.

 

 

 

Notes on main patterns:

 

·        The various patterns obtained through the possible combinations of the 4 IVMs or 4 fcc lattices are limited between the fcc lattices and the bcc lattice.

·        With 4 different lattices we can have a total combination of 6 pairs. And they are differentiated into two groups, group 1a with 2 combinations and 1b with 4 combinations.

·         The 2 pairs in I-1a, II-1a, III-1a, are always complementary, and their combination lead directly to the final stage the bcc lattice.

·        The 4 pairs in I-1b, II-1b, III-1b, are the new 4 lattices that can combine in the same way as the previous 4 lattices.

·        I do not know if this repeating pattern goes on indefinitely, it appears that at III-2 we start seeing a redundancy where it suggest an end to the 4 pairs pattern. The 4 pairs become in essence 2 pairs due to redundancy.